For the following table : Class 2 - 9 10 - 17 18 - 25 26 - 33 frequency 3 2 25 10 The 30th percentile is:
يبحث الطلاب في "مـوقـع التـرتيـب" عن حلول واجبات وأسئلة المناهج الدراسية، لأن التعليم هو أحد أهم عوامل التنمية والتقدم في المجتمعات، فهو يساهم في بناء الفرد وتطوير قدراته ومهاراته، ويؤثر بشكل كبير على حياته الشخصية والاجتماعية، وبفضل التعليم يستطيع الشخص تحقيق طموحاته وأهدافه في الحياة وفيما يلي نقدم لكم حل السؤال الآتي
حل سؤال : For the following table : Class 2 - 9 10 - 17 18 - 25 26 - 33 frequency 3 2 25 10 The 30th percentile is
الإجابة هي :
To find the 30th percentile, we first need to calculate the total number of observations in the data set.
Total frequency = 3 + 2 + 25 + 10 = 40
Next, we need to find the position of the 30th percentile in the ordered data set. Since the cumulative frequency at class 18-25 is already greater than or equal to 30, we know that the 30th percentile falls within this class
Now, we can use the following formula to calculate the percentile:
Percentile = L + (N/100) * w
Where:
L = Lower boundary of the class interval containing the desired percentile
N = Total number of observations
w = Width of the class interval
Cumulative frequency before desired percentile = Cumulative frequency at previous class interval
For our example:
L = 18 (lower boundary of class interval)
N = 40 (total number of observations)
w = width of class interval = upper boundary - lower boundary
Percentile = 18 + ((30 - 25) / 10) * (25 - 18)
Percentile = 18 + (5 /10) *7
Percentile = 18 + (0.5) *7
Percentile = 18 +3.5
Percentile=21.5
Therefore, the value at the 30th percentile is approximately equal to or less than Class Interval [21-28]
في الختام نتمى لكم التوفيق والنجاح.